A particle has its position moved from `vec(r_(1))=3hati+4hatj` to `vec(r_(2))=hati+2hatj`. Calculate the displacment vector `(Delta vecr)` and draw the `vec(r_(1)), vec(r_(2)) and Delta vecr` vector in a two dimensional Cartesian coordinate system.

Answer

Given: Position vectors `vecr_(1)=3hati+4hatj`
`vecr_(2)=hati+2hatj`

Explanation

Displacement vector: `Deltavecr=vecr_(2)-vecr_(1)=(1-3)hati+(2-4)hatj`
`Deltavecr=-2hati-2hatj=-2(hati+hatj)`