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In oblique projection, maximum horizonta...

In oblique projection, maximum horizontal range of the projectile is

A

`(u^(2)sin^(2)theta)/(2g)`

B

`(usintheta)/(g)`

C

`(u^(2)sin2theta)/(g)`

D

`(u^(2))/(g)`

Text Solution

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The correct Answer is:
A, B
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FULL MARKS-KINEMATICS-ADDITIONAL QUESTIONS SOLVED (I.MULTIPLE CHOICE)
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