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A meter long narrow bore held horizontal...

A meter long narrow bore held horizontally (and closed at one end) contains a 76 cm long mercury thread, which traps a 15 cm column of air. What happens if the tube is held vertically with the open end at the bottom?

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Then the heights of air column and mercury column are (24 + h) cm and (76 – h) cm respectively. The pressure of air = 76 – (76 – h) = h cm of mercury ∴ V2 = (24 + h) cm3 and P2 = h cm.
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