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The displacement of the particle along a...

The displacement of the particle along a straight line at time t is given by `X=a+bt+ct^(2)` where a, b, c are constants. The acceleration of the particle is

A

a

B

b

C

c

D

2c

Text Solution

Verified by Experts

The correct Answer is:
B, C

`X=a+bt+ct^(2)`
`(dX)/(dt)=v=b+2ct`
Acceleration `(d^(2)X)/(dt^2)=2c`
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