Consider an object of mass 2 kg resting on the floor. The coefficient of static friction between the object and the floor is `mu_8` = 0.8. What force must be applied on the object to move it?

Explanation

Since the object is at rest, the gravitational force experienced by an object is balanced by normal force exerted by floor.
N = mg
The maximum static frictional force `f_(s)^(max) = mu_s N = mu_s mg `
`f_(s)^(max) = 0.8 xx 2 xx 9.8 = 15.68 N`
Therefore to move the object the external force should be greater than maximum static friction.
` F_(ext) gt 15.68 N`