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A bob attached to the string oscillates ...

A bob attached to the string oscillates back and forth resolve the forces acting on the bob in to compents what is the acceleration experience by the bob at an angle `theta`

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The gravitational force (mg) acting downward can be resolved into two components as `mg cos theta ` and mg sin `theta` .
T-tension exerted by the string.
Tangential force `F_T - ma_T = mg sin theta `
Tangential acceleration `a_T = g sin theta `
Centripetal force ` F_C = ma_c = T- mg cos theta `
` therefore a_c = ((T - mg cos theta))/(m) `
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