Calculate the force required to move a train of 2000 quintal up on an incline plane of 1 in 50 with an acceleration of `2 ms^(-2)` . The force of friction per quintal is 0.5 N.

Explanation

Force of friction = 0.5 N per quintal
`f = 0.5 xx 2000 = 1000` per quintal
m = 2000 quintals =` 2000 xx 100` kg
` sin theta = 1/50 , a= 2m//s^2`
In moving up an inclined plane, force required against gravity
` = mg sin theta = 39200N`
And force required to produce acceleration = ma.
` = 2000 xx 100 xx 2 = 40,0000 N`
Total force required = 1000+ 39,200 + 40,0000 = 440200 N.