A hunter has a machine gun that can fire 50 g bullets with a velocity of `150ms^(-1)`. A 60 kg tiger springs at him with a velocity `10ms^(-1)` how many bullets must the hunter fire in to the tiger in order to stop him in his track

Explanation

Given `m_1` = mass of bullet = 50 g = 0.50 kg
`m_2` = mass of tiger = 60 kg
`v_1` = Velocity of bullet = 150 m/s
`v_2` = Velocity of tiger =- 10 m/s
( `because ` It is coming from opposite direction n = no. of bullets fired per second at the tiger so as to stop it.)
`P_i` = 0, before firing ...(1)
`P_f = n(m_1v_1) + m_2v_2` ...(2)
` because ` From the law of conservation of momentum,
`P_i = P_f`
` rArr 0 = n(m_1v_1) + m_2 v_2`
` rArr n = (m_2v_2)/(m_1v_1) = (-60 xx (-10))/(0.05 xx 150) = 80 `