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A force of (2hati+3hatj+5hatk)N is is ap...

A force of `(2hati+3hatj+5hatk)N` is is applied at a point whose position vector is `(7hati+4hatj-2hatk)m`. Find the torque of force about the origin.

Text Solution

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`vecr=7 hati+4hatj-2hatk`
`vecF=4hati-3hatj+5hatk`
Torque, `vec tau= vec r xx vec F`
`vectau=|{:(hati, hatj, hatk),(7,4,-2),(4,-3,5):}|`
`tau=hati(20-6)-hatj(35+8)+hatk(-21-16)`
`tau=(14hati-43hatk-37hatk) Nm`
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