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A jester in a circus is standing with hi...

A jester in a circus is standing with his arms extended on a turntable rotating with angular velocity c. He brings his arms closer to his body so that his moment of inertia is reduced to one third of the original value. Find his new angular velocity [Given: There is no external torque on the turn table in the given situation.]

Text Solution

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Let the moment of inertia of the jester with his arms extended bel. As there is no external torque acting on the jester and the tum table, his total angular momentum is conserved. We can write the equation,
`I_(i) omega_(i)=I_(f) omega_(f)`
`I_(i) omega_(i)=(1)/(3) I_(i) omega_(f)[ :. I_(f)=(1)/(3)I_(i)]`
`omega_(f)=3omega_(i)`
The above result tells that the final angular velocity is three times that of initial angol velocity
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