If the displacement of a particle is given by `s=2t^(3)-5t^(2)+4t-3`, then its acceleration is `14" ft/sec"^(2)` after to,e

If the displacement of a particle is given by s=2t^(3)-5t^(2)+4t-3 , then its velocity when acceleration is 14" ft/sec"^(2) , is

If the displacement of a particle is given by s=2t^(3)-5t^(2)+4t-3 , then its displacement when acceleration is 14" ft/sec"^(2) , is

The displacement of a particle at time t is given by s= 2t^(3) -5t^(2)+ 4t-3 . The time when the acceleration is 14ft/ sec^(2) is

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

If the displacement of a particle is x=t^(3)-4t^(2)-5t , then the acceleration of particle at t=2 is

If the displacement of a particle is x=t^(3)-4t^(2)-5t , then the velocity of particle at t=2 is

The displacement of a particle at time t is given by s= 2 t^3 - 5 t^2 + 4t -3. Find the time when the acceleration is 14 ft/ sec^2 , find the velocity and the displacement at that time.

The distance s of a particle in time t is given by s=t^3-6t^2-4t-8 . Its acceleration vanishes at t=