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A disc of moment of inertia la is rotati...

A disc of moment of inertia la is rotating in a horizontal plane about its symmetry axis with constant angular speed co. Another discinitially at rest of moment of inertia I, is dropped coaxially on to the rotating disc. Then, both the discs rotate with same constant angular speed The loss of kinetic energy due to friction in this process is,

A

`(1)/(2)(I_(b)^(2))/((I_(a)+I_(b))) omega^(2)`

B

`(I_(b)^(2))/((I_(a)+I_(b))) omega^(2)`

C

`((I_(b)-I_(a))^(2))/((I_(a)+I_(b))) omega^(2)`

D

`(1)/(2)(I_(b)I_(b))/(2(I_(a)+I_(b))) omega^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
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