A uniform rod of mass m and lengh I makes a constant angle `theta` with an axis of rotation which passes through one end of therod. Find the moment of inertia about this axis.

Explanation

Moment of inertia of the rod about the axis which is passing through its centre of gravity is
`I_(a)=(Ml^(2))/(12)=Ml^(2) sin^(2) theta//12`
Moment of inertia of a uniform rod of mass mand length / about one axis which passes through one end of the rod
`I_(0)=(Ml^(2) sin^(2) theta)/(4)=(Ml^(2)sin^(2) theta)/(12)+(Ml^(2) sin^(2) theta)/(4)=(1)/(3)Ml^(2) sin^(2) theta`