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Find the moment of inertia of a hydrogen...

Find the moment of inertia of a hydrogen molecule about an axis passing through its center of mass and perpendicular to the interatomic axis. Given : mass of hydrogen atom `1.7 xx 10^(-27)` kg and inter atomic distance is equal to `4 xx 10^(-10)` m.

Text Solution

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Given: Interatomic distance: `4xx 10^(-10)m`
Mass of `H_(2)=2M((R)/(2))^(2)=(1)/(2)MR^(2)`
`=(1)/(2)xx1.7xx10^(-27)xx16xx10^(-20)`
`=1.86xx10^(-46) kg m^(2)`
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