Two blocks of masses 10 kg and 4 kg are connected by a spring of negligible mass and placed on a frictionless horizontal surface. An impulse gives a velocity of 14 m's to the heavier block in the direction of the lighter block. The velocity of the center of mass is

Options

A. 30 m/s
B. 20 m/s
C. 10 m/s
D. 5 m/s

Answer

C

Explanation

According to law of conservation of lincar momentum
`MV=(M+M)V_(CM)`
`:.V_(CM)=(MV)/((M+M))=(10xx14)/(10+4)=10 ms^(-1)`