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A car weighs 1800 kg. The distance betwe...

A car weighs 1800 kg. The distance between its front and back axles is 1.8 m. Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front and back wheel.

Text Solution

Verified by Experts

For translational equilibrium of car
`N_(F)+N_(B)=W=1800xx9.8=17640 N`
For rotational equilibrium of car
`1*05N_(F)=0.75 N_(B)`
`1*05 N_(F)=0.75(1760-N_(F))`
`1.8N_(F)=13230`
`N_(F)=13230//1.8=7350 N`
`N_(B)=17640-7350=10290 N`
Force on each front wheel `=(7350)/(2)=3675 N`
Force on each back wheel `=(10290)/(2)=5145 N`
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