Calculated the change in g value in your district of Tamil nadu. (Hint : Get the latitude of your district of Tamil nadu from the Google). What is the difference in g values at Chennair and Kanyakumari?

Explanation

Variation of .g. value in the latitude to chennai
` g . ("Chennai") = g - omega^(2) R cos lambda `
Here `omega^(2)R = ((2Pi)/T)^(2) xxR `
Period of revolution (T) = 1 day = 86400 sec
Radius of the Earth (R ) = `6400 xx10^(3)` m
Latitude of Chennai `(lambda) = 13^(@) = 0.2268 ` rad
`g. _("Chennai") = 9.8 - [((2xx3.14)/(86400))^(2) xx 6400 xx10^(3)] xx (cos 0.2268 )^(2)`
` = 9.8 - [(3.4 xx10^(-2))xx(0.9744)^(2))] `
` = 9.8 - [ 0.034 xx 0.9494 ] = 9.8 - 0.0323 `
`g . _("Chennai") = 9.7677 "ms"^(-2)`
Variation of .g. value in the latitude of Kanyakumari
`lambda_("kanyakumari ") = 8^(@)35 . = 0.1457 ` rad
`g. _("Chennai") = 9.8 - [((2xx3.14)/(86400))^(2) xx 6400 xx10^(3)] xx (cos 0.2268 )^(2) - [3.4 xx10^(-2) xx (cos 0.1457)^(2) ] = 9.8 - 0.033 `
` g. _("kanyakumari") = 9.7667 ms^(-2)`
the difference of .g. value `Deltag = g._("Chennai") - g._("Kanyamukari")`
` = 9.7677 - 9.7667`
`Deltag = 0.001 "ms"^(-2)`