The period of revolution of planet A around the Sun is 8 times that of B. The distance of A from the Sun is how many times greater than that of B from the Sun.

Options

A. 2
B. 3
C. 4
D. 5

Answer

C

Explanation

`((T_(A))/(T_(B)))^(2)=((a_(A))/a_(B))^(2)rArr((8T_(B))/(T_(B)))^(2/3) =(a_(A))/(a_(B))`
`T_(A) =8T_(B) rArr(8)^(2/3) a_(B) = a_(A) rArr a_(A) = 4a_(B)`