The escape velocity of a body on the sur...

The escape velocity of a body on the surface of the Earth is 11.2km/s If the mass of the Earth is increase to twice its present value and the radius of the earth becomes half, the escape velocity becomes ` = ……"kms"^(-1)`

5.6

22.4

7.6

8.6

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The correct Answer is:

`v_(e) = sqrt((2GM)/(R))`

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