The escape velocity for a body projected...

The escape velocity for a body projected vertically upwards from the surface of Earth is `11 "kms"^(-1)`If the body is projected at an angle of`45^(@)` with verical, the escape velocity will be ........

`11/(sqrt(2))`

`11sqrt(2)`

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The correct Answer is:

Escape velocity does not depends upon the angle of projection

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