The time period of a satellite of Earth is 5 hours. If the separation between the Earth and the satellite is increased to four times the previous value, the new time period will become.

Explanation

`T_(2)=T_(1)((a_(2))/(a_(1)))^(3/2) = T_(1)[(4a_(1))/(a_(1))] ^(3/2) = 5(4)^(3/2) = 5(8)`
`T_(2) = 40` hours