Calculate the volume of one mole of any gas at STP and at room temperature (300K) with the same pressure 1 atm.

Explanation

Here STP means standard temperature (T = 273 K or `0^(@)C`)
and Pressure (P = 1 atm or 101.3 kPa)
We can use ideal gas equation `V=(muRT)/(P)`
Here `mu=1` mol and R = 8.314 J/mol.K
By substituting the value `V=("(1 mol)"(8.314(J)/(mol)K)(273K))/(1.013xx10^(5)Nm^(-2))=22.4xx10^(-3)m^(3)`
We know that 1 Litre `(L)=10^(-3)m^(3)`. So we can conclude that 1 mole of any ideal gas has volume 22.4 L
By multiplying 22.4 by `(300K)/(273K)` we get the volume of one mole of gas at room temperature.
It is 24.6 L