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An ideal gas passes from one equllibriu...

An ideal gas passes from one equllibrium state `(P_(1) ,V_(1), T_(1), N)` to anoter equilibrium state `(2P_(1) , 3V_(1), T_(2), N)` Then

A

`T_(1)=T_(2)`

B

`T_(1)=(T_(2))/(6)`

C

`T_(1)=6T_(2)`

D

`T_(1)=3T_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
From ideal gas equation, `PV=NkT`
One equilibrium state `(P_(1),V_(1),T_(1),N)`
Another equilibrium state `(P_(2), V_(2),T_(2),N)`
`P_(2)=2P_(1) and V_(2)=3V_(1)`
`(P_(1)V_(1))/(P_(2)V_(2))=(T_(1))/(T_(2))`
`(P_(1)V_(1))/(P_(2)V_(2))=(T_(1))/(T_(2))`
`(P_(1)V_(1))/((2P_(1))(3V_(1)))=(T_(1))/(T_(2)) rArr (1)/(6)=(T_(1))/(T_(2))`
`therefore" "T_(1)=(T_(2))/(6)`
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