An ideal gas is taken in a cyclic process as shown in the figure. Calculate
(a) work done by the gas. (b) work done on the gas (c ) Net work done in the process

Explanation

Work done by the gas (along AB)
`W=PxxDeltaV=600xx3=1800J, W=1.8kJ`
(b) Work is done on the gas (along BC)
`W=-PxxDeltaV=-400xx3=-1200J`
`W=-1.2kJ`
(c ) Net work done in the process = Area under the curve AB
`="Rectangle area "+"triangle area"`
`=(lxxb)+((1)/(2)xxbxxh)=(400xx3)+((1)/(2)xx3xx200)`
`=1200+300=1500J," "W=1.5kJ`