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A metallic solid sphere is rotating abou...

A metallic solid sphere is rotating about its diameter as axis of rotation. If the temperature is increased by `200^(@)C`. The percentage increase in its moment of inertia is : (coefficient of linear) expansion of the metal `=10^(-5)//^(@)C`)

A

0.1

B

0.2

C

0.3

D

0.4

Text Solution

Verified by Experts

The correct Answer is:
d
`I=(2)/(5)MR^(2)`
`(DeltaI)/(I)=2(DeltaR)/(R )=(2R alphat)/(R )=2alpha Deltat`
`(DeltaI)/(I)=2xx10^(-5)xx200=4xx10^(-3)`
`"Percentage increase "=4xx10^(-3)xx100=0.4`
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