2 Kg of water of 60^(@)C is mixed with 1...

2 Kg of water of `60^(@)C` is mixed with 1 kg of water at `30^(@)C` kept in a vessel of heat capacity `"220 J K"^(-1)`. The specific heat of water is `"4200 J Kg"^(-1)K^(-1)`. Then the final temperature is nearly.

(a) `35^(@)C`

(b) `45^(@)C`

(d) `50^(@)C`

Text Solution

Verified by Experts

The correct Answer is:

According to the principle of calorimetry,
`2xx4200xx(60-theta)=(14200+200)(theta-30)rArr theta =50^(@)C`

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