Ten moles of an ideal gas at constant te...

Ten moles of an ideal gas at constant temperature 600 K is compressed from 100l to 10L. The work done in the process is ……………. .

`4.11xx10^(4)J`

`-4.11xx10^(4)J`

`11.4xx10^(4)J`

`-11.4xx10^(4)J`

Text Solution

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The correct Answer is:

The process is isothermal. The work done is
`W=nRT ln ((V_(2))/(V_(1)))=2.3026xx10xx8.3xx600xxlog_(10)((10)/(100))rArr W=-11.4xx10^(4)J`

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