A flask is filled with 13 g of an ideal gas at `27^(@)C` and its temperature is raised to `52^(@)C`. Find the mass of the gas that has to be released to maintain the temperature of the gas in the flask at `52^(@)C` and the pressure is same as the initial pressure.

Explanation

Let n be the initial number of moles and n. be the final number of moles. Since pressure and volume remain the same, we have
`PV=nRT=nRxx300=n.Rxx325`
`(n.)/(n)=(300)/(325)=(12)/(13)`
`("Final mass")/("Initial mass")=(12)/(13)rArr" Final mass"=(12)/(13)xx13=12g`
`"Mass to be released "=13-12=1g`