Two vessels separately contain two ideal gases A and B at the same temperature, the pressure of A being twice that of B. Under such conditions, the density of A is found to be 1.5 times the density of B. The ratio of molecular weights of A and B is :

Explanation

According to the ideal gas equation for one mole,
`PV=RT`
`(PM)/(rho)=RT`
Where `rho` is the density and M is the molecular weight of the gas.
`M=(rhoRT)/(P)`
`(M_(A))/(M_(B))=(rho_(A))/(rho_(B)).(T_(A))/(T_(B)).(P_(B))/(P_(A))=1.5xx1xx(1)/(2)=(3)/(4)`
`M_(A):M_(B)=3:4`