(i) Find the adiabatic exponent `gamma` for mixture of `mu_1` moles of monoatomic gas and `mu_2` moles of a diatomic gas at normal temperature.
(ii) An oxygen molecule is travelling in air at 300 K and 1 atm , and the diameter of oxygen molecule is `1.2xx10^(-10)` m . Calculate the mean free path of oxygen molecule.

Explanation

`gamma=1/(sqrt2pind^(2))`
We have to find the number density n by usin ideal gas law
`n=N/V=P/(kT)=(101.3xx10^(3))/(1.381xx10^(-23)xx300)=2.499xx10^(25)"molecules/m"^(3)`
`gamma =1/(sqrt2xxpixx2.449xx10^(25)xx(1.2xx10^(-10))^(2))=1/(15.65xx10^(5))`
`gamma=0.63xx10^(-6)m`