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The ratio gamma=(C(P))/(C(V)) for a gas ...

The ratio `gamma=(C_(P))/(C_(V))` for a gas mixture consisting of 8 g of helium and 16 g of oxygen is

A

`(23)/(15)`

B

`(15)/(23)`

C

`(27)/(17)`

D

`(17)/(27)`

Text Solution

Verified by Experts

The correct Answer is:
c
Number of moles of helium `(n)=8/2=2`
Number of moles of oxygrn `(n.)=16/32=1/2`
In helium rtom, `C_(V)=3/2R`
Oxygen `C._(V)=5/2R`
`C_(V) ("mixture")= (nC_(V)+n.C._(V))/(n+n.)=((2xx3/2R)+(1/2xx5/2R))/((2+1/2))=17/10R`
`gamma ("mixtuer") =(C_(p))/(C_(v))=1 +(R)/(C_(v) ("mix"))=1+(R)/(((17)/(10)R))`
`gamma ("mixtuer") =27/17`
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