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If the temperature and pressure of a gas...

If the temperature and pressure of a gas is doubled the mean free path of the gas molecules

A

remains same

B

doubled

C

tripled

D

quadruples

Text Solution

Verified by Experts

The correct Answer is:
a
Mean free path of the molecule
`gamma=(kT)/(sqrt2pid^(2)P`
If T and P are double, `gamma=(2kT)/(sqrt2pid^(2)(2P))=(kT)/(sqrt2pid^(2)P)`
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