Home
Class 11
PHYSICS
From kinetic theory of gases, show that ...

From kinetic theory of gases, show that Moon cannot have atmosphere (Assume `k=1.38xx10^(-23)JK^(-1),T0^@C=273K)`.

Text Solution

Verified by Experts

At absolute temperature `T=0^(@)C=273`
Boltmann.s Constant `k_(B)=1.38xx10^(-23)JK^(-1)`
`m=3.33xx10^(27)` kg (mass of hydrogen molecule)
`nu_(rms)=sqrt((3k_(B)T)/m)=sqrt((3xx1.38xx10^(-23)xx273)/(3.33xx10^(27)))`
`sqrt((1130.22xx10^(-23))/(3.33xx10^(27)))=1824.11`
`nu_(rms)=1.84xx10^(13)ms^(-1)`
Promotional Banner

Topper's Solved these Questions

  • KINETIC THEORY OF GASES

    FULL MARKS|Exercise Additional Multiple Choise Questions|36 Videos
  • KINETIC THEORY OF GASES

    FULL MARKS|Exercise Additional 2- Mark Questions|11 Videos
  • KINETIC THEORY OF GASES

    FULL MARKS|Exercise Textual Evaluation Solved (III Long Answer Question)|8 Videos
  • KINEMATICS

    FULL MARKS|Exercise ADDITIONAL QUESTIONS SOLVED (LONG ANSWER QUESTIONS)|10 Videos
  • LAW OF MOTION

    FULL MARKS|Exercise ADDITIONAL QUESTIONS SOLVED (SHORT ANSWER QUESTIONS (3 MARKS & NUMERICALS))|16 Videos

Similar Questions

Explore conceptually related problems

Estimate the average energy of a helium atom at (i) room temperature (27^(@)C) (ii) the temperature on the surface of the sun (6000K) and (iii) the temperature of 10^(7) K. (k_(B)1.38xx10^(-23)JK^(-1))

A gas is at temperature 80^(@)C and pressure 5xx10^(-10)Nm^(-2) . What is the number of molecules per m^(3) if Boltzmann's constant is 1.38xx10^(-23)JK^(-1)

The average K.E. of a hydrogen gas molecule at STP will be (Boltmann canstant k_(B)=1.38xx10^(-23)JK^(-1).......