Home
Class 11
PHYSICS
Estimate the average energy of a helium ...

Estimate the average energy of a helium atom at (i) room temperature `(27^(@)C)` (ii) the temperature on the surface of the sun (6000K) and (iii) the temperature of `10^(7) K. (k_(B)1.38xx10^(-23)JK^(-1))`

Text Solution

Verified by Experts

Average K.E. per molecules is `barE=3/2k_(B)T`
(i) `T=27^(@)C+273=300K`
`barE=3/2xx1.38xx10^(-23)xx300=6.21xx10^(-21)J`
(ii) T=6000K
`barE=3/2xx1.38xx10^(-23)xx6000=1.242xx10^(-19)J`
(iii) `T=10^(7)K`
`barE =3/2xx1.38xx10^(-23)xx10^(7)=2.07xx10^(16)J`
Promotional Banner

Topper's Solved these Questions

  • KINETIC THEORY OF GASES

    FULL MARKS|Exercise Additional 2- Mark Questions|11 Videos

  • KINEMATICS

    FULL MARKS|Exercise ADDITIONAL QUESTIONS SOLVED (LONG ANSWER QUESTIONS)|10 Videos

  • LAW OF MOTION

    FULL MARKS|Exercise ADDITIONAL QUESTIONS SOLVED (SHORT ANSWER QUESTIONS (3 MARKS & NUMERICALS))|16 Videos

Similar Questions

Explore conceptually related problems

Water at temperature 100^(@)C cools in 10 minutes to 80^(@)C in a room temperature of 25^(@)C . Find (i) The temperature of water after 20 minutes (ii) The time when the temperature is 40^(@)C ["log"_(e)11/15=-0.3101,log_(e)5=1.6094]

Calculate the volume of one mole of any gas at STP and at room temperature (300K) with the same pressure 1 atm.

From kinetic theory of gases, show that Moon cannot have atmosphere (Assume k=1.38xx10^(-23)JK^(-1),T0^@C=273K) .

Find the average magnitude of linear momentum of a helium molecule in a sample of helium gas at 0^(@)C. Mass of a helium molecule =6.64xx10^(-27)kg and Blotzmann constant =1.38xx10^(-23) J K^(-1).

The average K.E. of a hydrogen gas molecule at STP will be (Boltmann canstant k_(B)=1.38xx10^(-23)JK^(-1).......

The energy required to raise the temperature of an iron ball by 1 K is 500 JK^(-1) . Calculate the amount of energy required to raise its temperature by 20 K.

A gas is at temperature 80^(@)C and pressure 5xx10^(-10)Nm^(-2) . What is the number of molecules per m^(3) if Boltzmann's constant is 1.38xx10^(-23)JK^(-1)