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Write down the time period of simple pen...

Write down the time period of simple pendulum.

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The angular frequency of this oscillator (natural frequency of this system) is
`omega^(2)=(g)/(l)`
`therefore omega=sqrt((g)/(l))` in rad `s^(-1)`
The frequency of oscillations is
`f=(1)/(2pi)sqrt((g)/(l))` in Hz
and time period of oscillations is
`T=2pisqrt((l)/(g))` in second
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