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The vertical extension in a light spring...

The vertical extension in a light spring by a weight of 1 kg, in equilibrium is 9.8 cm. The period of oscillation of the spring, in seconds, will be…………….

A

`(2pi)/(10)`

B

`(2pi)/(100)`

C

`20pi`

D

`200pi`

Text Solution

Verified by Experts

The correct Answer is:
A
`T=2pisqrt((l)/(g))=2pisqrt((9.8xx10^(-2))/(9.8))=(2pi)/(10)s`
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