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A body describes simple harmonic motion ...

A body describes simple harmonic motion with an amplitude of 5 cm and a period of 0.2s. Find the acceleration and velocity of the body when the displacement is 5 cm.

A

`(A)/(3)`

B

`(A)/(2)`

C

`(A)/(sqrt(2))`

D

`(A)/(2sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
Potential energy = `(1)/(2)` (Total energy)
`(1)/(2)momega^(2)y^(2)=(1)/(2)((1)/(2)momega^(2)A^(2))impliesy=(A)/(sqrt(2))`
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