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When the potential energy of a particle ...

When the potential energy of a particle executing simple harmonic motion is one-fourth of its maximum value during the oscillation, the displacement of the particle from the equilibrium position in terms of its amplitude a is………………

A

`(a)/(4)`

B

`(a)/(3)`

C

`(a)/(2)`

D

`(2a)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
C

`(1)/(2)momega^(2)y^(2)=(1)/(4)((1)/(2)momega^(2)a^(2))impliesy=(a)/(2)`
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