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A massless spring, having force constant...

A massless spring, having force constant k, oscillates with a frequency n when a mass m is suspended from it. The spring is cut into two equal halves and a mass 2m is suspended from one of the parts. The frequency of oscillation will now be………….

A

n

B

`nsqrt(2)`

C

`(n)/(sqrt(2))`

D

2n

Text Solution

Verified by Experts

The correct Answer is:
A
`n=(1)/(2pi)sqrt((k)/(m)),n.=(1)/(2)sqrt((2)/(2))=n`
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