The motion of a particle is expressed by the equation `a=-bx`, where x is the displacement from the mean position, a is the acceleration and b is a constant. The periodic time is……………

Options

A. `(2pi)/(b)`
B. `(2pi)/(sqrt(b))`
C. `2pisqrt(b)`
D. `2sqrt((pi)/(b))`

Answer

B

Explanation

Here `omega^(2)=b`. Therefore `T=(2pi)/(omega)=(2pi)/(sqrt(b))`