A particle of mass m is executing oscillations about the origin on the x-axis. Its potential energy is `V(x)=kx^(2)`. Where k is a positive constant. If the amplitude of oscillation is a, then its time period T is……………

Options

A. Proportional to `(1)/(sqrt(a))`
B. independent of a
C. proportional to `sqrt(a)`
D. proportional to `a^(3//2)`

Answer

B

Explanation

Since `V(x)=Kx^(2)`, the motion is simple harmonic. In SHM, the time period is independent of the amplitude of oscillation.