The period of oscillation of a simple pendulum is T in a stationary lift. If the lift moves upwards with an acceleration of 8g, the period will………….

Options

A. remain the same
B. decrease by T/2
C. increase by T/3
D. none of these

Answer

C

Explanation

`T=2pisqrt((l)/(g)),T.=2pisqrt((l)/(g+8g))=(1)/(3)(2pisqrt((l)/(g)))=(T)/(3)`
Thus, the new time period is `T//3`.