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A pendulum is hung from the roof of a su...

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is `20ms^(-2)` at a distance of 5 m from the mean position. To find the time period of oscillation.

Text Solution

Verified by Experts

`a=20ms^(-2),y=5m" "a=omega^(2)y`
`20=omega^(2)(5),omega^(2)=4`
`omega=2` rad/sec
Time period of oscillation,
`T=(2pi)/(omega)=(2pi)/(2)`
`T=pisec`
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Knowledge Check

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