An object is thrown with initial speed `5ms^(-1)` with an angle of projection `30^(@)`. What is the maximum height and range reached by the particle?

Explanation

Initial speed ` = 5ms^(-1)`
Angle of projection ` = 30^@`
Max height reached `h_(max) = (u^2 sin^2 theta)/(2g)`
` = (25 xx (1/2)^2 )/(2 xx 9.8 ) = (25)/(8 xx 9.8) = 0.319 m `
horizontal range ` = (u^2 sin 2 theta)/(g) = (25 xx sin 60^@)/(g) = (25 xx sqrt3)/(g) = (25 xx sqrt3)/(2 xx 9.8) = (43.3)/(19.6) = 2.21 m `