A body cools from `60^@`C to `50^@`C in 10 min of room If the room temperature is ` 25^@` C and assuming Newton's cooling law holds good, the temperature of the body after 10 more minute.

Explanation

According to newtons law of cooling
` ( theta_2 - theta_1)/(t) = k [ (theta_2 + theta_1)/(2) - theta_0 ]`
` therefore (60 - 50)/(10) = k [ (60 + 50)/(2) - 25]`
` 1 = 30 k " or " k = 1/30`
` (50 - theta)/(10) = k [ (50 + theta)/(2) - 25 ] = k theta / 2 = (theta)/(60)`
or ` 70 theta = 3000, theta = 300/7 = 42.8^@C`