Consider two springs with force constants `1 Nm^(-1)` and `2Nm^(-1)` connected in parallel. Calculate the effective spring constant `(k_(p))` and comment on `k_(p)`.

Explanation

` k_1 = 1 Nm^(-1) , k_2 = 2Nm^(-1)`
` k_p = k_1 + k_2 + Nm^(-1)`
`k_p = 1 + 2 =3 Nm^(-1)`
` k_p gt k_1 " and " k_p gt k_2`
Therefore, the effective spring constant is greater than both `k_1 " and " k_2`