Home
Class 11
PHYSICS
Convert a velocity of 72 km h^(1-) into ...

Convert a velocity of 72 km `h^(1-)` into `ms^(-1)` with the help of dimensional analysis.

Text Solution

Verified by Experts

`n_1 = 72 km h^(-1) `
` n_2 = ? `
` L_1 = 1km `
` L_2= 1m`
` T_1 = 1h`
` T_2 = 1s`
` n_2 = n_1 [L_1/L_2]^a [T_1/T_2]^b`
The dimensional formula for velocity is ` [LT^(-1) ]`
a = 1 b = 1
`n_2 = 72 [ (1km)/(1m) ] [ (1h)/(1s) ]^(-1)`
` = 72 [ (1000 m )/(1m) ]^1 [ (3600s)/(1s) ]^(-1) = 72 xx 1000 xx 1//3600 = 20 ms^(-1)`
` = 72 km h^(-1) = 20 ms^(-1)`
Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER - 2

    FULL MARKS|Exercise PART-III|9 Videos
  • PROPERTIES OF MATTER

    FULL MARKS|Exercise Additional Questions Solved - Numerical Questions|19 Videos
  • SAMPLE PAPER - 18 (UNSOLVED)

    FULL MARKS|Exercise PART - IV|10 Videos

Similar Questions

Explore conceptually related problems

A cricket ball of mass 0.5 kg strikes a bat normally with a velocity of "30 ms"^(-1) and rebounds with a velocity of "20 ms"^(-1) in the opposite direction, calculate the impulse of the force exerted by the ball on the bat.

A body of mass 2 kg moving with uniform velocity of 40 ms^(-1) collides with another body at rest . If two bodies move together with a velocity of 20 ms^(-1) . Find the mass of the other body .

A particle moves in a straight line with a constant acceleration. It changes its velocity from 10ms^(-1) to 20ms^(-1) while passing through a distance 135m in t second. The value of t is:

Check the correctness of the equation 1/2 mv^(2) = mgh using dimensional analysis method.