Home
Class 11
PHYSICS
Convert 3 ms^(-2) "to km" h^(-2) (ii)...

Convert
3 `ms^(-2) "to km" h^(-2)` (ii) G = `6.67 xx 10^(-11)` N `m^(2) kg^(-2)` to `cm^(3) g^(-1) s^(-2)`

Text Solution

Verified by Experts

(i) `3ms^(-2) = (3/1000 km) ( (1)/(60 xx 60) hr)^(-2)`
` = (3 xx (60 xx 60)^2)/(1000) = 3.8880 xx 10^4 km h^(-2) = 3.9 xx 10^4 km h^(-2)`
(ii) ` G = 6.67 xx 10^(-11) Nm^2 kg^(-2)`
` = 6.67 xx 10^(-11) (kg ms^(-2) ) (m^2 kg^(-2) )`
` = 6.67 xx 10^(-11) kg^(-1) m^3 s^(-2)`
` = 6.67 xx 10^(-11) (1000 g)^(-1) (100 cm)^3 (s^(-2)) `
` = 6.67 xx 10^(-11) xx 1/1000 xx 100 xx 100 g^(-1) cm^3 s^(-2)`
`= 6.67 xx 10^(-8) g^(-1) cm^3 s^(-2)`
Promotional Banner

Topper's Solved these Questions

  • SAMPLE PAPER - 2

    FULL MARKS|Exercise PART-III|9 Videos
  • PROPERTIES OF MATTER

    FULL MARKS|Exercise Additional Questions Solved - Numerical Questions|19 Videos
  • SAMPLE PAPER - 18 (UNSOLVED)

    FULL MARKS|Exercise PART - IV|10 Videos

Similar Questions

Explore conceptually related problems

G = 6.67xx10^(-11) N m^(2)(kg)^(-2) = ………. (cm)^(3)s^(-2)g^(-1) .

Universal gravitational constant (a) G = 6.684 xx 10^(-10) Nm^(2) kg^(-1)

A satellite orbits the earth at a height of 400 km above the surface. How much energy must be expended to rocket the satellite out of the earth’s gravitational influence? Mass of the satellite = 200 kg, mass of the earth = 6.0 ×x 10^(24) kg, radius of the earth = 6.4 xx 10^(6) m , G = 6.67 xx 10^(-11) N m^(2)) kg^(-2) .

A spaceship is stationed on Mars. How much energy must be expended on the spaceship to launch it out of the solar system ? Mass of the space ship = 1000 kg, mass of the sun = 2 xx 10^(30) kg , mass of mars = 6.4 xx 10^(23) kg, radius of mars = 3395 Km: radius of the orbit of mars = 2.28 xx 10^(8) km , G = 6.67 xx 10^(-11) N m^(2) kg^(-2) .

Calculate the product of the uncertainties of displacement and velocity of a moving electron having a mass of 9.1 xx 10^(-28) g . Given : h = 6.626 xx 10^(-34) kg m^2 s^(-1) m = 9.1 xx 10^(-28) g = 9.1 xx 10^(-31) kg

A rocket is fired vertically with a speed of 5 km s^(-1) from the earth’s surface. How far from the earth does the rocket go before returning to the earth ? Mass of the earth = 6.0 x× 10^(24) kg, mean radius of the earth = 6.4 xx 10^(6) m , G = 6.67 xx 10^(-11) " N "m^(2) kg^(-2) .

A rocket is fired ‘vertically’ from the surface of mars with a speed of 2 km s^(–1) . If 20% of its initial energy is lost due to martian atmospheric resistance, how far will the rocket go from the surface of mars before returning to it ? Mass of mars = 6.4 ×x 10^(23) kg, radius of mars = 3395 km, G = 6.67 xx 10^(-11) N m^(2) Kg^(-2) .