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The parallax of a heavenly body measured...

The parallax of a heavenly body measured from two points diametrically opposite on equator of Earth is `2^(1)`. Calculate the distance of the heavenly body. [Given radius of the Earth = 6400 km][1" = `4.85 xx 10^(-6)` rad]

A

`8.8xx10^(10) m`

B

`4.4 xx 10^(10) m`

C

`0.29xx10^(-10)`m

D

`8.6xx10^(-10)m`

Text Solution

Verified by Experts

The correct Answer is:
B
`theta =1 min =(1)/(60) xx (pi)/( 1800) rad`
diameter of earth , ` d=a xx R_(e) = 2xx 6400 xx 10^(3) m`
distance of the heavenly body from the centre of the earth ,` r= (d) /( theta) =( 2xx 6400 xx 10^(3) )/( ((pi)/( 60xx80)))`
` r= 4.4 xx 10^(10) m`
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