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If the velocity is vec(v) = 2 hat(i) + ...

If the velocity is `vec(v) = 2 hat(i) + t^(2) hat(j) - 9 vec(k)`, then the magnitude of acceleration at t = 0 . 5 s is :

A

`1 ms^(-2)`

B

`2 ms^(-2)`

C

zero

D

`-1 ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`a = (dv )/(dt) =(d) /( dt) ( 2 hati + t^2 hatj - 9 hatk ) = 2 t hatj`
at ` t= 0.5 s implies a= 2 ( 0.5 ) =1 ms^(-2)`
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